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Need tiebreaker advice - settling H2H when uneven amounts of games (1 Viewer)

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kardplayer

Footballguy
I'm taking a fresh look at tiebreaker rules in my league in advance of the season and wanted to get the shark pools thoughts. We have 12 teams, 3 divisions, and a 13 week regular season. You play 2 of the three teams in your division 2 and one of them once. As a result, there are a few tiebreaker scenarios that can get hairy. Specifically, if the team that plays 4 games goes 2-2, does the tiebreaker get settled or does it advance to the next tiebreaker step.

I'll share my thoughts/decision later, but want to get your thoughts first.

Your opinions are greatly appreciated.

 
Best answer: Don't use head to head as a fantasy tiebreaker. In the NFL, your defense affects the opponent's offense and vice versa. Both team's points directly reflect on the opponent's team so it's a true test against each other. In fantasy, your points are mostly independent of who your opponent is. As a way of determining the better team, it's not much better than using both team's point totals in some randomly selected week whether they played each other or not. So go with something more meaningful.

Next best answer: If you must use it, for multiple team tiebreaks it only finds a winner if one team swept all other teams in the tiebreak. This is how the NFL does it, incidentally.

At least not a horrible answer: H2H only used if all teams played each other the same amount of times. If they have, it's straight winning percentage.

Other options after those are pretty much bad enough I wouldn't even recommend considering them.

 
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Best answer: Don't use head to head as a fantasy tiebreaker. In the NFL, your defense affects the opponent's offense and vice versa. Both team's points directly reflect on the opponent's team so it's a true test against each other. In fantasy, your points are mostly independent of who your opponent is. As a way of determining the better team, it's not much better than using both team's point totals in some randomly selected week whether they played each other or not. So go with something more meaningful.

Next best answer: If you must use it, for multiple team tiebreaks it only finds a winner if one team swept all other teams in the tiebreak. This is how the NFL does it, incidentally.

At least not a horrible answer: H2H only used if all teams played each other the same amount of times. If they have, it's straight winning percentage.

Other options after those are pretty much bad enough I wouldn't even recommend considering them.
Generally, we love H2H as a tiebreaker.

The NFL actually uses the "At least not a horrible answer" tiebreaker - if there are three teams tied in the division, you don't need to sweep to win. 3-1 vs. 2-2 and 1-3 equals the 3-1 team winning the tiebreaker. If it's across divisions, then the sweep rule comes into play.

I'm leaning towards "no one" on the first, since everyone beat one team , and on the other one I'm torn between C (since A "had their chance" but couldn't sweep B or C, while C is undefeated vs. B) and "no one" since the records are the same as the first one and it would seem odd that the same records would have different outcomes.

 

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