The_Man
Footballguy
I'm trying to figure out AFC playoff seeding -- I think this is right.
If the Ravens, Texans, and Patriots all finish tied at 13-3, then they'll all be 10-2 in the AFC. Head-to-head won't apply, since they haven't all played each other. And Common Games won't apply, because they don't have four Common Games. That means the tie-breaker would be Strength of Victory. Baltimore has a big edge here:
Baltimore = 62 (2 win over Pitt and one over SF alone are worth 28 and counting, plus every HOU win adds to the Ravens' tally)
New England = 45
Houston = 41 (two wins over Jax and Indy only count for 6)
At 13-3, Baltimore wins a two-way tie over Houston on head-to-head, and over New England on Common Games (5-0 vs. 4-1 against PITT, NYJ, SD, Indy).
If Baltimore loses, and Pittsburgh gets into a three-way tie at 13-3, they would be eliminated from the tie with a 7-3 conference record. In that scenario, Houston and New England would have the same AFC record, be 4-1 vs. Common Opponents (MIA, OAK, Indy, Pitt) and the tie-breaker for the #1 seed would still be Strength of Victory. This same tie-breaker also applies to determining who would be the #2 seed if Baltimore were to get the #1 as outlined above. If Pittsburgh gets into a two-way tie with NE, they are #1, but if they are in a two-way tie with Houston, they are #2 (based on head-to-head in both situations).
In the West, with Denver and Oakland tied at 7-5, the Broncos hold a couple of advantages. One, the Broncos have already clinched the Common Games tie-breaker (if these teams finish tied): Oakland went 2-0 vs. non-common opponents, while the Broncos went 1-1. That means if they finish with the same number of wins, the Broncos will have one more win vs. Common Opponents. The tie-breaker before that is division record. Denver is 3-2 in the division while Oakland is 2-2. If you figure both these teams will probably lose at least one more game, the Raiders can't afford for that loss to be in the division. Because Denver has already clinched the Common Games tie-breaker, the Raiders lose if they finish with the same AFC West record as the Broncos.
Wild Card is way too crazy to figure out right now. Same is true with the top seeds if they finish at 12-4 instead of 13-3. Could be pretty amazing for the Steelers to finish 13-3 and end up as a #5 seed, playing at 9-7 Oakland or Denver. Also, the Ravens could go into Week 17 at Cincy needing a win to be #1, or falling all the way to #5 with a loss. I just don't see the Ravens ending the season on a 7-game winning streak, so my playoff prediction is:
1: Pittsburgh (13-3)
2: New England (13-3)
3: Houston (11-5)
4: Denver (9-7)
5: Baltimore (12-4)
6: Can't make an educated guess yet.
If the Ravens, Texans, and Patriots all finish tied at 13-3, then they'll all be 10-2 in the AFC. Head-to-head won't apply, since they haven't all played each other. And Common Games won't apply, because they don't have four Common Games. That means the tie-breaker would be Strength of Victory. Baltimore has a big edge here:
Baltimore = 62 (2 win over Pitt and one over SF alone are worth 28 and counting, plus every HOU win adds to the Ravens' tally)
New England = 45
Houston = 41 (two wins over Jax and Indy only count for 6)
At 13-3, Baltimore wins a two-way tie over Houston on head-to-head, and over New England on Common Games (5-0 vs. 4-1 against PITT, NYJ, SD, Indy).
If Baltimore loses, and Pittsburgh gets into a three-way tie at 13-3, they would be eliminated from the tie with a 7-3 conference record. In that scenario, Houston and New England would have the same AFC record, be 4-1 vs. Common Opponents (MIA, OAK, Indy, Pitt) and the tie-breaker for the #1 seed would still be Strength of Victory. This same tie-breaker also applies to determining who would be the #2 seed if Baltimore were to get the #1 as outlined above. If Pittsburgh gets into a two-way tie with NE, they are #1, but if they are in a two-way tie with Houston, they are #2 (based on head-to-head in both situations).
In the West, with Denver and Oakland tied at 7-5, the Broncos hold a couple of advantages. One, the Broncos have already clinched the Common Games tie-breaker (if these teams finish tied): Oakland went 2-0 vs. non-common opponents, while the Broncos went 1-1. That means if they finish with the same number of wins, the Broncos will have one more win vs. Common Opponents. The tie-breaker before that is division record. Denver is 3-2 in the division while Oakland is 2-2. If you figure both these teams will probably lose at least one more game, the Raiders can't afford for that loss to be in the division. Because Denver has already clinched the Common Games tie-breaker, the Raiders lose if they finish with the same AFC West record as the Broncos.
Wild Card is way too crazy to figure out right now. Same is true with the top seeds if they finish at 12-4 instead of 13-3. Could be pretty amazing for the Steelers to finish 13-3 and end up as a #5 seed, playing at 9-7 Oakland or Denver. Also, the Ravens could go into Week 17 at Cincy needing a win to be #1, or falling all the way to #5 with a loss. I just don't see the Ravens ending the season on a 7-game winning streak, so my playoff prediction is:
1: Pittsburgh (13-3)
2: New England (13-3)
3: Houston (11-5)
4: Denver (9-7)
5: Baltimore (12-4)
6: Can't make an educated guess yet.