Kleck
Footballguy
Pays the bills.Have you guys been going non-stop all day?![]()
I admire your dedication to mathematics![]()

Pays the bills.Have you guys been going non-stop all day?![]()
I admire your dedication to mathematics![]()
Cool (maybe).You sound like my law professors.It should be pinned as a reminder of the perils of considering something to be simple.Is this thread finally going to die? We can only hope.
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
7-18This alludes back to an earlier post, but what would your answers be for these?
4 x 2³ - 5² =
2 x 3² - 6² =
What a gem. Why explain or clarify your point so everyone can understand it when you know you're right and you can just jam it down their throats. Very tactical approach. Please tell me you don't teach or manage people.Sorry but when someone that supposedly has a doctoral in math begins his answer with "You really should be precise" I'm out. The question is precise to anyone that understands convention.Dr. Rick needs more schooling.Yes, there were (and still are?) a few people saying that -5^2=-25 is wrong.Smoo wasn't, though. He was just saying it's stupid. Not that the people who follow the convention are stupid, but that the convention itself is stupid.Thread title "I beleive the teacher is wrong", shick agreed with the teacher, by the distributive property, the original poster probably thought shick was wrong too for a while, along with others.
We've talked him down from stupid to arbitrary, I think. (I would keep going past arbitrary all the way to sensible.)Squaring Negative Numbers
Date: 02/19/2002 at 10:59:10
From: Thanh Phan
Subject: Squaring negative numbers
Hello,
I would like to know: does -9^2 = 81 or -81?
--------------------------------------------------------------------------------
Date: 02/19/2002 at 12:38:08
From: Doctor Rick
Subject: Re: Squaring negative numbers
Hi, Thanh.
You really should be precise about what you are asking in this case,
since (-9)^2 means -9 times -9, but the expression -9^2 could also be
taken to mean -(9^2), that is, the negative of the square of 9, which
is -81.
When we're working with variables, if we see -x^2, we interpret it in
the second way, as -(x^2), because squaring (or any exponentiation)
takes precedence over negation (or any multiplication; -x is treated
as -1*x.
When you have numbers only, as in -9^2, it's not at all clear that we
should treat it differently from -x^2. However, some will argue that
it should, because -9 represents a single number, not an operation on
a number. Thus, some will interpret -9^2 as (-9)^2, while others will
read it as -(9^2).
Because of the difference of opinion, I highly recommend that you put
in the parentheses explicitly whenever this situation arises.
- Doctor Rick, The Math Forum
http://mathforum.org/dr.math/![]()
OMG! Tommyboy is right! He's proven beyond a shadow of a doubt that the entire mathematical community on the planet is wrong! I feel so inadequate.Dude, do you have a tux? You're gonna need one for the Nobel ceremony.lets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
however it is obvious as well that -5^2= +25 if you read it as negative five, squared, which most people will if it is written as in integer, that is -5^2. If it is written as -x^2, then it is known that x must be squared first then made negative by rule. However when it is written as an actual integer, in this case -5, then it is NOT known by rule that (-) sign in front is an operative or a value. Since it is not known by rule then it is required of the writer to make clear the question so the reader understands if -5^2 means negative five, squared or if it means five squared, negative.
I still refuse to accept this "-1*5^2" nonsense as an explanation.If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2. But that obviously doesn't get you the same result.I didn't have enough time to read all of this thread, but I have enjoyed what I've read of the discussion.![]()
![]()
I remember a lot of people had troubles with this concept. The 2 explanations I specifically remember have been mentioned long ago. Either add 0 to each side, or think of it as -1*5^2 and then use the basic order of operations. Factoring out the -1 made the most sense to me, and that concept really helped in polynomial factorization and simplification later in algebra and calculus.
While opposition points have been interesting, I'm just going to take it on faith that mathematicians have this concept right. I mean Andrew Wiles spent most of his adult life trying to prove Fermat's Last Theorem:
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).lets review^2 = yandx = -5therefore, literally replacing the x with -5 the new equation reads-5^2 = ynow it is the convention, allegedly, that -5^2= -25 because it is implied as -(5^2).
No, you can't rewrite 4^2 as 2*2^2, since "4" doesn't contain an operator that means "multiply the square root of the operand by itself" (or whatever).The unary minus, on the other hand, is an operator that means "multiply the operand by negative one." So -5 can be rewritten as (-1)(5).I still refuse to accept this "-1*5^2" nonsense as an explanation.
If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2.
Here I am, stuck in the middle with you...
That's amazing.Mathematics is the language of engineers. Getting this fundamental problem wrong is like a writer not being able to conjugate "is".They still require math for an engineering degree, don't they? They did when I got mine.This post needs more love. Add one more engineer to your list that got it wrong the first time.
It's basic mathematical languagelets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
however it is obvious as well that -5^2= +25 if you read it as negative five, squared, which most people will if it is written as in integer, that is -5^2. If it is written as -x^2, then it is known that x must be squared first then made negative by rule. However when it is written as an actual integer, in this case -5, then it is NOT known by rule that (-) sign in front is an operative or a value. Since it is not known by rule then it is required of the writer to make clear the question so the reader understands if -5^2 means negative five, squared or if it means five squared, negative.
After reading the rest of this thread,I still refuse to accept this "-1*5^2" nonsense as an explanation.If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2. But that obviously doesn't get you the same result.I didn't have enough time to read all of this thread, but I have enjoyed what I've read of the discussion.![]()
![]()
I remember a lot of people had troubles with this concept. The 2 explanations I specifically remember have been mentioned long ago. Either add 0 to each side, or think of it as -1*5^2 and then use the basic order of operations. Factoring out the -1 made the most sense to me, and that concept really helped in polynomial factorization and simplification later in algebra and calculus.
While opposition points have been interesting, I'm just going to take it on faith that mathematicians have this concept right. I mean Andrew Wiles spent most of his adult life trying to prove Fermat's Last Theorem:
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
There are ways of explaining the situation well, Maurile has accomplished it, but invoking "-1*5" is a completely incorrect way of doing it.
I think many people are getting confused because the negative is being linked to a "1". -5^2 can turn into (-1)(5^2) but 4^2 can not turn into 2*2^2. The reason that the 1 appears from nowhere is because in order to factor out the negative you need to link it to a numeral. Being that 1 is the multiplicative identity, you can link it to a "1" without altering the answer to the problem.No, you can't rewrite 4^2 as 2*2^2, since "4" doesn't contain an operator that means "multiply the square root of the operand by itself" (or whatever).The unary minus, on the other hand, is an operator that means "multiply the operand by negative one." So -5 can be rewritten as (-1)(5).I still refuse to accept this "-1*5^2" nonsense as an explanation.
If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2.
The "-1*5^2" explanation works perfectly well once you understand the unary minus to be an operator that negatives the operand (by multiplying it by negative one).
They weeded math out of most advanced structural engineering degrees somewhere in the 60's. You should get up to speed. Toss the solution in your resume and maybe you can get a leg upThat's amazing.Mathematics is the language of engineers. Getting this fundamental problem wrong is like a writer not being able to conjugate "is".This post needs more love. Add one more engineer to your list that got it wrong the first time.
They still require math for an engineering degree, don't they? They did when I got mine.
[johnbelushi]uhhh, sorry[/johnbelushi]You people still here?
BTW, this is exactly like stating that, according to what we have been arguing, if you replace x with -5 then 9x looks like this:9-5not according to what you guys have been arguing.if you replace x with -5 then the equation looks like this:(-5)^(-25)what would the answer be here:
X^(-5^2) if X= -5
-5^-25
which based on what Gray and Shick and yourself were saying would be
the same as -(5^-25) not (-5)^(-25)
the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).lets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
If taking a number to the second power isn't an operation, why are exponents contained in the order of operations? Do you believe multiplication is an operation?Edit: -5^2 expresses -(5)*(5) which expresses -(5+5+5+5+5)the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).lets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
So what is 8/5^2?When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
I'm pretty much done with this thread. Tommy, at some point you have to realize you're in a sword fight holding a toothpick.the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).lets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
QuitterI'm pretty much done with this thread. Tommy, at some point you have to realize you're in a sword fight holding a toothpick.the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).lets review:
x^2 = y
and
x = -5
therefore, literally replacing the x with -5 the new equation reads
-5^2 = y
now it is the convention, allegedly, that
-5^2= -25 because it is implied as -(5^2).
Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Never started.Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Never starterer.Never started.Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Never starterer.Never started.Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Hey, teacher, leave that kid alone!Never starterer.Never started.Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
Hey, teacher, leave that kid alone!Never starterer.Never started.Quitter.Let me check. Am I in school? No. Guess I won't be doing it teach.Find all integer solutions for x.(x^2 - 7x +13)^(x^2 - 11x +30) = 1Quitter
Clock starts now.
8/5 x 8/5= 64/25.So what is 8/5^2?When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
Oh my.8/5 x 8/5= 64/25.So what is 8/5^2?
Here we go again...Oh my.8/5 x 8/5= 64/25.So what is 8/5^2?
In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.8/5 x 8/5= 64/25.So what is 8/5^2?When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
I meant 8/5^2.If there are no parentheses, you apply the operations in their proper order. Exponentiation comes first -- whether we're talking about 8/5^2 or -5^2.were somewhat limited here by the computer interface, since I can't tell if MT means
(8/5)^2 or 8/(5^2).
I assumed he meant the first
Well looky here now tommy. Ya see, we have these rules in math that we use to avoid confusion. We call them the order of operations. Your gut, your opinion, your feelings, well... they don't mean ####.You can go back to where ever you got a high school diploma and beat the mother living piss out of whoever was responsible for allowing you to pass, or you can just accept that you don't quite grasp what we're talking about here. Who knows, maybe you were too busy dreaming about Mary Jane Rottencrotch during math class. Whatever. I don't care much at the moment. I'm fairly drunk right now and somewhat amazed I can actually type. Thank God for all those typing classes.were somewhat limited here by the computer interface, since I can't tell if MT means
(8/5)^2 or 8/(5^2).
I assumed he meant the first
Well looky here now tommy. Ya see, we have these rules in math that we use to avoid confusion. We call them the order of operations. Your gut, your opinion, your feelings, well... they don't mean ####.You can go back to where ever you got a high school diploma and beat the mother living piss out of whoever was responsible for allowing you to pass, or you can just accept that you don't quite grasp what we're talking about here. Who knows, maybe you were too busy dreaming about Mary Jane Rottencrotch during math class. Whatever. I don't care much at the moment. I'm fairly drunk right now and somewhat amazed I can actually type. Thank God for all those typing classes.were somewhat limited here by the computer interface, since I can't tell if MT means
(8/5)^2 or 8/(5^2).
I assumed he meant the first
In closing, if you choose to procreate, please promise me you won't help your kids in their math classes. TIA.
In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.8/5 x 8/5= 64/25.So what is 8/5^2?When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
Are we clear?
I love it. I have more math experience than probably 90% of this board and you're telling me I don't get it. I get it. If you fail as the writer of the question to ask the question the way you want it answered, you don't get it. If Maurile wants an answer to (8/5)^2 then ask that. If he wants an answer to 8/(5^2) then ask that. Simple really. This isn't even an argument. It just is. a real number squared, is a real number squared. In the original question that started this mess, the question was "what is the base negative 5 squared?" as it was written. It would be no different if the question had been what is x^-x and x = -5, then the expression would be -5^5. However if the question was asked without variables and instead expressed as -5^-5 then the answer would be far different.In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.8/5 x 8/5= 64/25.So what is 8/5^2?When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
Are we clear?