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Daughter's math homework (1 Viewer)

I didn't have enough time to read all of this thread, but I have enjoyed what I've read of the discussion. :nerd: :bag: I remember a lot of people had troubles with this concept. The 2 explanations I specifically remember have been mentioned long ago. Either add 0 to each side, or think of it as -1*5^2 and then use the basic order of operations. Factoring out the -1 made the most sense to me, and that concept really helped in polynomial factorization and simplification later in algebra and calculus. While opposition points have been interesting, I'm just going to take it on faith that mathematicians have this concept right. I mean Andrew Wiles spent most of his adult life trying to prove Fermat's Last Theorem:

Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.
 
This alludes back to an earlier post, but what would your answers be for these?

4 x 2³ - 5² =

2 x 3² - 6² =
7-18

In this case, I read the - as an operation. :P

Starting an equation with an operation makes no sense to me. Would you write:

+5^2? Of course not, because when the 5 is written on its own the + is implied. When you put the - there, you're signifying its negativity.

 
Thread title "I beleive the teacher is wrong", shick agreed with the teacher, by the distributive property, the original poster probably thought shick was wrong too for a while, along with others.
Yes, there were (and still are?) a few people saying that -5^2=-25 is wrong.Smoo wasn't, though. He was just saying it's stupid. Not that the people who follow the convention are stupid, but that the convention itself is stupid.

We've talked him down from stupid to arbitrary, I think. (I would keep going past arbitrary all the way to sensible.)
Squaring Negative Numbers

Date: 02/19/2002 at 10:59:10

From: Thanh Phan

Subject: Squaring negative numbers

Hello,

I would like to know: does -9^2 = 81 or -81?

--------------------------------------------------------------------------------

Date: 02/19/2002 at 12:38:08

From: Doctor Rick

Subject: Re: Squaring negative numbers

Hi, Thanh.

You really should be precise about what you are asking in this case,

since  (-9)^2 means -9 times -9, but the expression -9^2 could also be

taken to mean -(9^2), that is, the negative of the square of 9, which

is -81.

When we're working with variables, if we see -x^2, we interpret it in

the second way, as -(x^2), because squaring (or any exponentiation)

takes precedence over negation (or any multiplication; -x is treated

as -1*x.

When you have numbers only, as in -9^2, it's not at all clear that we

should treat it differently from -x^2. However, some will argue that

it should, because -9 represents a single number, not an operation on

a number. Thus, some will interpret -9^2 as (-9)^2, while others will

read it as -(9^2).

Because of the difference of opinion, I highly recommend that you put

in the parentheses explicitly whenever this situation arises.

- Doctor Rick, The Math Forum

  http://mathforum.org/dr.math/  
Dr. Rick needs more schooling.
:wall:
Sorry but when someone that supposedly has a doctoral in math begins his answer with "You really should be precise" I'm out. The question is precise to anyone that understands convention.
What a gem. Why explain or clarify your point so everyone can understand it when you know you're right and you can just jam it down their throats. Very tactical approach. Please tell me you don't teach or manage people.
 
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lets review:x^2 = yandx = -5therefore, literally replacing the x with -5 the new equation reads-5^2 = ynow it is the convention, allegedly, that -5^2= -25 because it is implied as -(5^2).however it is obvious as well that -5^2= +25 if you read it as negative five, squared, which most people will if it is written as in integer, that is -5^2. If it is written as -x^2, then it is known that x must be squared first then made negative by rule. However when it is written as an actual integer, in this case -5, then it is NOT known by rule that (-) sign in front is an operative or a value. Since it is not known by rule then it is required of the writer to make clear the question so the reader understands if -5^2 means negative five, squared or if it means five squared, negative.

 
lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).

however it is obvious as well that -5^2= +25 if you read it as negative five, squared, which most people will if it is written as in integer, that is -5^2. If it is written as -x^2, then it is known that x must be squared first then made negative by rule. However when it is written as an actual integer, in this case -5, then it is NOT known by rule that (-) sign in front is an operative or a value. Since it is not known by rule then it is required of the writer to make clear the question so the reader understands if -5^2 means negative five, squared or if it means five squared, negative.
OMG! Tommyboy is right! He's proven beyond a shadow of a doubt that the entire mathematical community on the planet is wrong! I feel so inadequate.Dude, do you have a tux? You're gonna need one for the Nobel ceremony.

 
I didn't have enough time to read all of this thread, but I have enjoyed what I've read of the discussion. :nerd: :bag:

I remember a lot of people had troubles with this concept. The 2 explanations I specifically remember have been mentioned long ago. Either add 0 to each side, or think of it as -1*5^2 and then use the basic order of operations. Factoring out the -1 made the most sense to me, and that concept really helped in polynomial factorization and simplification later in algebra and calculus.

While opposition points have been interesting, I'm just going to take it on faith that mathematicians have this concept right. I mean Andrew Wiles spent most of his adult life trying to prove Fermat's Last Theorem:

Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.
I still refuse to accept this "-1*5^2" nonsense as an explanation.If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2. But that obviously doesn't get you the same result.

There are ways of explaining the situation well, Maurile has accomplished it, but invoking "-1*5" is a completely incorrect way of doing it.

 
lets review:x^2 = yandx = -5therefore, literally replacing the x with -5 the new equation reads-5^2 = ynow it is the convention, allegedly, that -5^2= -25 because it is implied as -(5^2).
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).
 
I still refuse to accept this "-1*5^2" nonsense as an explanation.

If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2.
No, you can't rewrite 4^2 as 2*2^2, since "4" doesn't contain an operator that means "multiply the square root of the operand by itself" (or whatever).The unary minus, on the other hand, is an operator that means "multiply the operand by negative one." So -5 can be rewritten as (-1)(5).

The "-1*5^2" explanation works perfectly well once you understand the unary minus to be an operator that negatives the operand (by multiplying it by negative one).

 
This post needs more love. Add one more engineer to your list that got it wrong the first time.
That's amazing.Mathematics is the language of engineers. Getting this fundamental problem wrong is like a writer not being able to conjugate "is".They still require math for an engineering degree, don't they? They did when I got mine.
 
lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).

however it is obvious as well that -5^2= +25 if you read it as negative five, squared, which most people will if it is written as in integer, that is -5^2.  If it is written as -x^2, then it is known that x must be squared first then made negative by rule.  However when it is written as an actual integer, in this case -5, then it is NOT known by rule that (-) sign in front is an operative or a value.  Since it is not known by rule then it is required of the writer to make clear the question so the reader understands if -5^2 means negative five, squared or if it means five squared, negative.
It's basic mathematical language:x^2=y means that y equals the quantity that x represents, squared. That's simple. If that quantity is (-5) then the (-5) is being squared. If the quantity is (-5*2+3) then its' that entire quantity being squared. Whatever quantity x represents, it gets squared.

Also, when you read:

-x^2=y , you should read "y equals the quantity that x represents, squared, times negative 1." X represents a quantity, and it will be multiplied by negative 1 and also squared. According to the OoO, you square first and multiply later. So if x equals the quantity of five, it's assumed to be written like -(5)^2=y.

When you read:

-5^2=y, you should read "y equals the quantity 5 squared, times negative 1." It's unclear what quantity is being squared, and if it's not specified that the quantity is (-5), then you assume it's (-1)(5)^2.

I'd like to know what grade this homework was given in, as this is really one of the basic principles of math.

 
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I didn't have enough time to read all of this thread, but I have enjoyed what I've read of the discussion. :nerd: :bag:

I remember a lot of people had troubles with this concept. The 2 explanations I specifically remember have been mentioned long ago. Either add 0 to each side, or think of it as -1*5^2 and then use the basic order of operations. Factoring out the -1 made the most sense to me, and that concept really helped in polynomial factorization and simplification later in algebra and calculus.

While opposition points have been interesting, I'm just going to take it on faith that mathematicians have this concept right. I mean Andrew Wiles spent most of his adult life trying to prove Fermat's Last Theorem:

Fermat's last theorem (so called because it was the last of the results which Fermat claimed and which had not been proved) states that if n > 2 then the equation x^n + y^n = z^n has no positive integer solutions.
That is dedication. I seriously doubt guys like that would overlook this one if there were any hint that it's not true.
I still refuse to accept this "-1*5^2" nonsense as an explanation.If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2. But that obviously doesn't get you the same result.

There are ways of explaining the situation well, Maurile has accomplished it, but invoking "-1*5" is a completely incorrect way of doing it.
After reading the rest of this thread, :bag: , I shouldn't have said it was factoring out the -1. But it is still -1*5^2 as Maurile explained it a few posts up.
 
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I still refuse to accept this "-1*5^2" nonsense as an explanation.

If stuff like that were permissible, then I could take something like 4^2 and rewrite it as 2*2^2.
No, you can't rewrite 4^2 as 2*2^2, since "4" doesn't contain an operator that means "multiply the square root of the operand by itself" (or whatever).The unary minus, on the other hand, is an operator that means "multiply the operand by negative one." So -5 can be rewritten as (-1)(5).

The "-1*5^2" explanation works perfectly well once you understand the unary minus to be an operator that negatives the operand (by multiplying it by negative one).
I think many people are getting confused because the negative is being linked to a "1". -5^2 can turn into (-1)(5^2) but 4^2 can not turn into 2*2^2. The reason that the 1 appears from nowhere is because in order to factor out the negative you need to link it to a numeral. Being that 1 is the multiplicative identity, you can link it to a "1" without altering the answer to the problem.
 
This post needs more love.  Add one more engineer to your list that got it wrong the first time.
That's amazing.Mathematics is the language of engineers. Getting this fundamental problem wrong is like a writer not being able to conjugate "is".

They still require math for an engineering degree, don't they? They did when I got mine.
They weeded math out of most advanced structural engineering degrees somewhere in the 60's. You should get up to speed. Toss the solution in your resume and maybe you can get a leg up :thumbup:
 
I know a guy who once argued on a math/science message board that Einstein's E = mc^2 was wrong. He said it should actually be E = mc^3. He was not a mathematician or scientists. He was just some schmoe who thought he was really smart. Needless to say, that didn't go well for him.

 
what would the answer be here:

X^(-5^2) if X= -5
(-5)^(-25)
not according to what you guys have been arguing.if you replace x with -5 then the equation looks like this:

-5^-25

which based on what Gray and Shick and yourself were saying would be

the same as -(5^-25) not (-5)^(-25)
BTW, this is exactly like stating that, according to what we have been arguing, if you replace x with -5 then 9x looks like this:9-5

which based on what we have been saying would be the same as (9-5) not 9(-5).

The answer is: uh, no, that's not what we've been saying.

It is true that 9-5 is is the same as (9-5) (i.e., it is 4). But it is not true that 9x turns into 9-5 when x is -5. You can't just substitute the characters "-5" in there wherever you see "x" and expect the result to be coherent. You would be fine, however, if you substituted "(-5)" in there.

 
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lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).
the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.

 
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lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).
the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
If taking a number to the second power isn't an operation, why are exponents contained in the order of operations? Do you believe multiplication is an operation?Edit: -5^2 expresses -(5)*(5) which expresses -(5+5+5+5+5)

 
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When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
So what is 8/5^2?
 
lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).
the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
I'm pretty much done with this thread. Tommy, at some point you have to realize you're in a sword fight holding a toothpick.
 
lets review:

x^2 = y

and

x = -5

therefore, literally replacing the x with -5 the new equation reads

-5^2 = y

now it is the convention, allegedly, that

-5^2= -25 because it is implied as -(5^2).
No, that's wrong.x is negative five. So when we square x, we have to square negative five. To square negative five, we have to write it as "(-5)^2". If you were to write it as "-5^2", you would be failing to insert x anywhere in there. The expression "-5^2" does not contain a negative five anywhere. What is negative in that expression is not five, but twenty-five (since exponentiation comes before the unary minus).
the expression -5^2 is not an expression. An expression would be -x^2. The figure -5^2 contains only one operation and that is the exponent of negative five. When you write a variable say X or Y or Z as a representation and put it in a formula then you practice the order of operations. When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
I'm pretty much done with this thread. Tommy, at some point you have to realize you're in a sword fight holding a toothpick.
Quitter
 
When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
So what is 8/5^2?
8/5 x 8/5= 64/25.
 
When  you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
So what is 8/5^2?
8/5 x 8/5= 64/25.
In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.

Are we clear?

 
were somewhat limited here by the computer interface, since I can't tell if MT means (8/5)^2 or 8/(5^2).I assumed he meant the first

 
were somewhat limited here by the computer interface, since I can't tell if MT means

(8/5)^2 or 8/(5^2).

I assumed he meant the first
I meant 8/5^2.If there are no parentheses, you apply the operations in their proper order. Exponentiation comes first -- whether we're talking about 8/5^2 or -5^2.

 
were somewhat limited here by the computer interface, since I can't tell if MT means

(8/5)^2 or 8/(5^2).

I assumed he meant the first
Well looky here now tommy. Ya see, we have these rules in math that we use to avoid confusion. We call them the order of operations. Your gut, your opinion, your feelings, well... they don't mean ####.You can go back to where ever you got a high school diploma and beat the mother living piss out of whoever was responsible for allowing you to pass, or you can just accept that you don't quite grasp what we're talking about here. Who knows, maybe you were too busy dreaming about Mary Jane Rottencrotch during math class. Whatever. I don't care much at the moment. I'm fairly drunk right now and somewhat amazed I can actually type. Thank God for all those typing classes.

In closing, if you choose to procreate, please promise me you won't help your kids in their math classes. TIA.

 
were somewhat limited here by the computer interface, since I can't tell if MT means

(8/5)^2  or  8/(5^2).

I assumed he meant the first
Well looky here now tommy. Ya see, we have these rules in math that we use to avoid confusion. We call them the order of operations. Your gut, your opinion, your feelings, well... they don't mean ####.You can go back to where ever you got a high school diploma and beat the mother living piss out of whoever was responsible for allowing you to pass, or you can just accept that you don't quite grasp what we're talking about here. Who knows, maybe you were too busy dreaming about Mary Jane Rottencrotch during math class. Whatever. I don't care much at the moment. I'm fairly drunk right now and somewhat amazed I can actually type. Thank God for all those typing classes.

In closing, if you choose to procreate, please promise me you won't help your kids in their math classes. TIA.
:lmao:
 
When  you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
So what is 8/5^2?
8/5 x 8/5= 64/25.
In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.

Are we clear?
:lmao:
 
When you simply write a real number that is -5, or 3 or 1/2 or 8/5 or any real number you do not apply the positive or negative after the fact, because that positive or negative is the value of the number, not an operation.
So what is 8/5^2?
8/5 x 8/5= 64/25.
In case anyone was wondering, we reserve the lowest levels of hell for those that don't grasp basic math facts.I know we had an agreement tommy, but unless you learn the order of operations correctly the deal is off.

Are we clear?
I love it. I have more math experience than probably 90% of this board and you're telling me I don't get it. I get it. If you fail as the writer of the question to ask the question the way you want it answered, you don't get it. If Maurile wants an answer to (8/5)^2 then ask that. If he wants an answer to 8/(5^2) then ask that. Simple really. This isn't even an argument. It just is. a real number squared, is a real number squared. In the original question that started this mess, the question was "what is the base negative 5 squared?" as it was written. It would be no different if the question had been what is x^-x and x = -5, then the expression would be -5^5. However if the question was asked without variables and instead expressed as -5^-5 then the answer would be far different.

writing

-5^2= y produces the correct answer of 25. Thanks for playing. Good night.

 

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