I like math, but not gambling. No idea what constitutes a “pull tab”.Nobody likes math
I’m sure I could figure this out but I’d bet someone like @Ignoratio Elenchi will do it
To calculate the odds of getting 6 out of the 15 winners in a drawing with 6000 entries, we need to use combinatorics.
The total number of ways to choose 6 winners out of the 15 available winners is given by the combination formula:
C(n, r) = n! / (r!(n-r)!),
where n is the total number of items and r is the number of items to be chosen.
In this case, n = 15 (total number of winners) and r = 6 (number of winners to be chosen).
C(15, 6) = 15! / (6!(15-6)!) = 5005.
So, there are 5005 possible combinations of choosing 6 winners out of the 15.
Now, let's calculate the odds. Odds are typically expressed as the ratio of the number of successful outcomes to the number of unsuccessful outcomes.
The number of successful outcomes is 1 because you want to calculate the odds of getting exactly 6 winners.
The number of unsuccessful outcomes is the total number of combinations minus the number of successful outcomes:
Unsuccessful outcomes = Total combinations - Successful outcomes
= 5005 - 1
= 5004.
Therefore, the odds of getting 6 out of the 15 winners in a drawing with 6000 entries are 1:5004.
Exactly. Either you win or you don't.50/50
100How many tickets did you pull?
no. the odds of getting 1 is 6000:1. there is no way that getting 6 is only 5000:1To calculate the odds of getting 6 out of the 15 winners in a drawing with 6000 entries, we need to use combinatorics.
The total number of ways to choose 6 winners out of the 15 available winners is given by the combination formula:
C(n, r) = n! / (r!(n-r)!),
where n is the total number of items and r is the number of items to be chosen.
In this case, n = 15 (total number of winners) and r = 6 (number of winners to be chosen).
C(15, 6) = 15! / (6!(15-6)!) = 5005.
So, there are 5005 possible combinations of choosing 6 winners out of the 15.
Now, let's calculate the odds. Odds are typically expressed as the ratio of the number of successful outcomes to the number of unsuccessful outcomes.
The number of successful outcomes is 1 because you want to calculate the odds of getting exactly 6 winners.
The number of unsuccessful outcomes is the total number of combinations minus the number of successful outcomes:
Unsuccessful outcomes = Total combinations - Successful outcomes
= 5005 - 1
= 5004.
Therefore, the odds of getting 6 out of the 15 winners in a drawing with 6000 entries are 1:5004.
C(15, 6) / C(6000, 100)100How many tickets did you pull?
I think the odds of getting 1 of 15 winners in a pool of 6000 tickets is better than 6000:1. Especially if you’re drawing 100 tickets.no. the odds of getting 1 is 6000:1. there is no way that getting 6 is only 5000:1To calculate the odds of getting 6 out of the 15 winners in a drawing with 6000 entries, we need to use combinatorics.
The total number of ways to choose 6 winners out of the 15 available winners is given by the combination formula:
C(n, r) = n! / (r!(n-r)!),
where n is the total number of items and r is the number of items to be chosen.
In this case, n = 15 (total number of winners) and r = 6 (number of winners to be chosen).
C(15, 6) = 15! / (6!(15-6)!) = 5005.
So, there are 5005 possible combinations of choosing 6 winners out of the 15.
Now, let's calculate the odds. Odds are typically expressed as the ratio of the number of successful outcomes to the number of unsuccessful outcomes.
The number of successful outcomes is 1 because you want to calculate the odds of getting exactly 6 winners.
The number of unsuccessful outcomes is the total number of combinations minus the number of successful outcomes:
Unsuccessful outcomes = Total combinations - Successful outcomes
= 5005 - 1
= 5004.
Therefore, the odds of getting 6 out of the 15 winners in a drawing with 6000 entries are 1:5004.
C(15, 6) / C(6000, 100)I'm just guessing, by the way. But I'd go to bat for it.
Seems right. 15 out of 6000 is the same as 1 in 400.And your odds of getting a pull tab with one ticket pulled is actually one in four hundred. I think.
Idk that's what chatgpt gave and it's not always right.no. the odds of getting 1 is 6000:1. there is no way that getting 6 is only 5000:1To calculate the odds of getting 6 out of the 15 winners in a drawing with 6000 entries, we need to use combinatorics.
The total number of ways to choose 6 winners out of the 15 available winners is given by the combination formula:
C(n, r) = n! / (r!(n-r)!),
where n is the total number of items and r is the number of items to be chosen.
In this case, n = 15 (total number of winners) and r = 6 (number of winners to be chosen).
C(15, 6) = 15! / (6!(15-6)!) = 5005.
So, there are 5005 possible combinations of choosing 6 winners out of the 15.
Now, let's calculate the odds. Odds are typically expressed as the ratio of the number of successful outcomes to the number of unsuccessful outcomes.
The number of successful outcomes is 1 because you want to calculate the odds of getting exactly 6 winners.
The number of unsuccessful outcomes is the total number of combinations minus the number of successful outcomes:
Unsuccessful outcomes = Total combinations - Successful outcomes
= 5005 - 1
= 5004.
Therefore, the odds of getting 6 out of the 15 winners in a drawing with 6000 entries are 1:5004.
6000/100Yesterday I was playing pull tabs at a local bar. The game had 6000 tickets (assume none had been played). There are 15 tickets that are scratch offs, so you can win the main prizes. I put $100 in and got 6 of the scratch offs on the first pull. What were the odds?