That's the one part of your argument I don't understand. Yes, it's 50% less likely that they'll get a TD + 2, but it's also 50/50 that Seattle gets the 2 and goes up 9, which increases their win probability dramatically. So isn't the decision to go for two just the equivalent of betting on your offense to get a two-pointer rather than your defense to prevent one?
Again, I think it was wrong for the "information" reason, but I don't understand the "math" argument against it. I see that as a coin flip.
I'll explain my reasoning then:
Going for 2 is a coin flip. (I actually disagree with that because it assumes league average, rather than against "X team", and the Seahawks' pass defense is well above league average, but I'll throw the propeller heads a bone here and ignore that logic fail)
Kicking the PAT and going up 8 is a 95% certainty. (which again is considering league average, not how totally money Hauschka has been with chip shot PATs - I'd put it closer to 99%, but ok, I concede to the propeller heads yet again, and will allow guys like Blair Walsh to drag down the #s and dictate what % of success Hauschka would have based on league ave)
There aren't 2 possible outcomes here, there are 4.
1. Kick the PAT and go up by 8, forcing a TD+2 point attempt
2. Miss the FG and be up 7, a TD+PAT ties the game This has been described as a 5% chance
3. Convert the 2 pt attempt and go up 9, effectively salting away the game
4. Converting the 2 pt attempt and failing, up 7, a TD+PAT ties the game, a TD+2 pt attempt wins the game for the Pats (not unprecedented, Oakland did so earlier this year)
Scenario #1 would have been a 95% certainty, resulting in the outcome where the Pats had to score a TD, then convert a 2 point attempt, to result in a
tie. So again, and not without merit, the worst case scenario here is the Patriots tie the game. And that's identifying this scenario as having the highest probability of success for the Seahawks to convert (95%, 99%, whatever you believe)
Scenario #2 is essentially the same result as scenario #4, so unless you lack confidence in your kicker / ST (see: AZ Cards, MIN Vikes, etc) then the PAT is pretty well a lock.
Scenarios #3 & #4 in fact
reduces the Seahawks chances of success by 45% t
o convert points after the TD, (while of course increasing their chances of winning the game
if successful). However,
a failure to convert keeps the game spread at 7, and actually opens the door for a possible outcome of NEP scoring 8 and winning the game on that final drive. So here the worst possible scenario is that you give up a TD and 2 point conversion and actually
lose the game. So while it increases the chance to win, the odds of success are cut by ~half, and the worst case scenario goes from 0% chance to lose to a % chance to lose equal to the size of BB's nutsack if he should decide to go for 2. (note: I doubt BB would go for 2 to win, but you never know, and some % chance to lose > none % chance to lose)
Sure, the upside to converting the 2 point attempt is that you're a lock to win, but that's a 50-50 chance compared to going up 8, which still makes it substantially harder for the Pats to tie than a PAT, had the Pats scored.
So all things considered, and given the percentages of success for each possible approach, it certainly seems like the scenario that gives the Seahawks the best chance of winning (and with none chance of losing) would be to kick the PAT, be up by 8, and force the Pats to drive down the field and convert two offensive plays with worst case scenario avoided, in that even if BOTH were successful the worst thing that happens is tie game/overtime.
I'm not sure how that's a coin flip. Maybe someone better at math can educate me.